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42 votes
42 votes
In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lottery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning

User Rvabdn
by
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1 Answer

4 votes
4 votes

Answer:


Pr =(1)/(38955840)

Explanation:

Given


n = 35 ---- 1 to 35


r = 5 -- selection

Required

The probability of winning

The probability of getting the first number correctly is:


P(1) = (1)/(35)

At this point, the remaining numbers are 34

So, the second selection has the following probability


P(2) = (1)/(34)

Following the above sequence, we have:


P(3) = (1)/(33)


P(4) = (1)/(32)


P(5) = (1)/(31)

So, the required probability is:


Pr =P(1) * P(2) * P(3) * P(4) * P(5)


Pr =(1)/(35) *(1)/(34)*(1)/(33)*(1)/(32)*(1)/(31)


Pr =(1)/(35*34*33*32*31)


Pr =(1)/(38955840)

User Asiimwe
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