Question

What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?

x = –2 + StartRoot StartFraction 1 Over 2 EndFraction EndRoot or x = –2 – StartRoot StartFraction 1 Over 2 EndFraction EndRoot
x = 2 + StartRoot StartFraction 1 Over 2 EndFraction EndRoot or x = 2 – StartRoot StartFraction 1 Over 2 EndFraction EndRoot
x = –2 + StartRoot StartFraction 23 Over 6 EndFraction EndRoot or x = –2 – StartRoot StartFraction 23 Over 6 EndFraction EndRoot
x = 2 + StartRoot StartFraction 23 Over 6 EndFraction EndRoot or x = 2 – StartRoot StartFraction 23 Over 6 EndFraction EndRoot

Answer 1

`x=(12+√(138))/(6)\:\:or\:\:x=(12-√(138))/(6)`

Explanation:

`f(x)=6x^2-24x+1\\\\0=6x^2-24x+1\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\x=(-(-24)\pm√((-24)^2-4(6)(1)))/(2(6))\\ \\x=(24\pm√(576-24))/(12)\\\\x=(24\pm2√(138))/(12)\\\\x=(12\pm√(138))/(6)`

Answer 2

Answer: D

Step-by-step explanation: On edge 2020