Question

Compound J, C16H16Br2, is optically active. On treatment with strong base, compounds K and L (each C16H14) are formed; K and L each absorb only 2 equivalents of hydrogen when reduced over a Pd/C catalyst. Compound K reacts with ozone to give phenylacetic acid (C6H5CH2COOH), while similar treatment of L gives 2 products. One product, M, is an aldehyde with formula C7H6O; the other product is glyoxal (CHO)2. Draw the structure of compound M.

Answer 1

attached below

Step-by-step explanation:

Attached below is the structure of compound M

Compound J, C₁₆H₁₆Br₂

Compounds K and L = C₁₆H₁₄ each

Phenylacetic acid = C₆H₅CH₂COOH