Question

A force of 1.6 N is needed to stretch a spring 0.8 meter. How much PE is stored in this spring, when stretched 0.8 m ?

Answer 1

Step-by-step explanation:

A force of 1.6 N is needed to stretch a spring 0.8 meter

spring constant = force / extension

k = 1.6 / .8 = 2 N/ m

potential energy PE = 1/2 k X² where X is extension

= .5 x 2 x .8²

= .64 J .