Question

2.0 kilograms of lithium hydroxide can “scrub”, or remove, how many liters of carbon dioxide at standard conditions?

Answer 1

0.94 L

Step-by-step explanation:

The equation of the reaction is;

2LiOH + CO2 -----> Li2CO3 + H2O

Number of moles LiOH = 2.0/23.95 g/mol = 0.084 moles

2 moles of LiOH scrubs 22.4 L of CO2

0.084 moles of LiOH scrubs 0.084 moles × 22.4/2

= 0.94 L