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Which is the correct calculation of the y-coordinate of point A? 0 (0 - 0)2 + (1 - y2 = 2 O (0 - 1)² + (0- y2 = 22 (0-0)² + (1 - y2 = 2 (0 - 1)2 + (0-y2 = 2​

Which is the correct calculation of the y-coordinate of point A? 0 (0 - 0)2 + (1 - y-example-1
User Armamut
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3.1k points

1 Answer

14 votes
14 votes

Answer:

The y-coordinate of point A is
√(3).

Explanation:

The equation of the circle is represented by the following expression:


(x-h)^(2)+(y-k)^(2) = r^(2) (1)

Where:


x - Independent variable.


y - Dependent variable.


h,
k - Coordinates of the center of the circle.


r - Radius of the circle.

If we know that
h = 0,
k = 0 and
r = 2, then the equation of the circle is:


x^(2) + y^(2) = 4 (1b)

Then, we clear
y within (1b):


y^(2) = 4 - x^(2)


y = \pm \sqrt{4-x^(2)} (2)

If we know that
x = 1, then the y-coordinate of point A is:


y = \sqrt{4-1^(2)}


y = √(3)

The y-coordinate of point A is
√(3).

User Kaspars
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3.0k points