Question

By the third day of a particular week, 2 accidents have already occurred in the intersection. What is the probability that there will be less than a total of 4 accidents during that week

Answer 1

The right answer is "0.70".

Explanation:

The given query seems to be incomplete. Please find below the attachment of the full query.

By using the Bayes' theorem, we get

⇒
`P[(X<4)|(X \geq 2)] = (P(2 \leq X < 4))/(P(X \geq 2))`

By putting the values, we get

`=([P(2)+P(3)])/([1-P(0)-P(1)])`

`=((0.20+0.15))/(1-0.20-0.30)`

`=(0.35)/(0.5)`

`=0.70`