Question

An empty parallel plate capacitor is connected between the terminals of a 18.8-V battery and charges up. The capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor

Answer 1

`p.d' = 37.6 V`

Step-by-step explanation:

From the question we are told that:

Potential difference
`p.d=18.8V`

New Capacitor
`C_1=C_2/2`

Generally the equation for Capacitor capacitance is mathematically given by

`C=(eA)/(d)`

Generally the equation for New p.d' is mathematically given by

`C_2V=C_1*p.d'`

`p.d' = 2V`

`p.d'= 2 * 18.8`

`p.d' = 37.6 V`