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The perimeter of rhombus EFGH is 48 cm and the measure of ZFE) = 60

The perimeter of rhombus EFGH is 48 cm and the measure of ZFE) = 60-example-1
User Victor Ejiogu
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1 Answer

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12 votes

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Answer:

a. 12 cm

b. 90°

c. 60°

Explanation:

The relevant relationships are ...

  • all sides of a rhombus have the same length
  • the diagonals of a rhombus are perpendicular bisectors of each other
  • the diagonals of a rhombus divide the figure into 4 congruent triangles

__

a) The perimeter, 48 cm, is the sum of four equal side lengths, so any given side is (48 cm)/4 = 12 cm.

GH = 12 cm

__

b) Angle EJF is where the diagonals meet. It is a right angle.

∠EJF = 90°

__

c) Angle EFJ is the complement of the one marked, so is 30°. Angles EHJ and GHJ are congruent to that, so both are 30°. Angle EHG is the sum of those two congruent 30° angles, so is ...

∠EHG = 60°

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