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PLEASE HELP!!! (question is in image)

PLEASE HELP!!! (question is in image)-example-1
User Overseas
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Explanation:

We can find the maximum profit by taking the derivative of the profit and then solving for the widget price x that will maximize it. It is done by equating the derivative to zero:


(dy)/(dx) = -12x + 600 = 0

Solving for x, we get


x = (600)/(12) = \$50

By setting the widget price to $50, the company can maximize their profits. To find this maximum profit, substitute the value of x into the equation for the profit:


y = -6(50)^2 + 600(50) - 5726


\;\;\;=\$9,274

User Jnnks
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