Explanation:
We can find the maximum profit by taking the derivative of the profit and then solving for the widget price x that will maximize it. It is done by equating the derivative to zero:
![(dy)/(dx) = -12x + 600 = 0](https://img.qammunity.org/2023/formulas/mathematics/college/cicutz1840a7tvtriltxzdxmnilytaqpck.png)
Solving for x, we get
![x = (600)/(12) = \$50](https://img.qammunity.org/2023/formulas/mathematics/college/85lhfjtkurzn8akmg3k36v7jr6i3gicgi3.png)
By setting the widget price to $50, the company can maximize their profits. To find this maximum profit, substitute the value of x into the equation for the profit:
![y = -6(50)^2 + 600(50) - 5726](https://img.qammunity.org/2023/formulas/mathematics/college/8jflsuggatxybuw96uj21trx3ty3ec9u5x.png)
![\;\;\;=\$9,274](https://img.qammunity.org/2023/formulas/mathematics/college/cvngv28izgx3h05kljp2hhpf6vc8ld7ze0.png)