Question

A4.60pf capacitor that is initially uncharged is connected in series with a 7.50kohms resistor and an emf source with E=125V and negligible internal resistance. Just after the circuit is completed, what are; a. The voltage drop across the capacitor b. The voltage drop across the resistor c. The charge on the capacitor d. The current through the resistor e.

Answer 1

a)
`V_c=0`

b)
`V_R=145V`

c)
`Q_c=0`

d)
`I=(1)/(60)A`

Step-by-step explanation:

From the question we are told that:

Capacitor
`C=4.60`

Resistor
`R=7.50`

Source emf
`E=125V`

a)

Generally The voltage drop across the capacitor is

V_c=0

b)

Generally the equation for Voltage drop is mathematically given by

`V=IR`

`V=(E)/(R)*R`

`V_R=145V`

c

Generally The Charge across the capacitor is

`Q_c=0`

d)

Generally the equation for Current is mathematically given by

`I=(V)/(R)`

`I=(125)/(7.5*10^3)`

`I=(1)/(60)A`