Question

What are the roots of the quadratic equation below?
2x^2 – 5x-1=0

Answer 1

`x_1=(5+√(33))/(4)\approx2.6861\\ \\x_2=(5-√(33))/(4)\approx-0.1861`

Explanation:

`2x^2-5x-1=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\ \\x=(-(-5)\pm√((-5)^2-4(2)(-1)))/(2(2))\\ \\x=(5\pm√(25+8))/(4)\\ \\x=(5\pm√(33))/(4)\\ \\x_1=(5+√(33))/(4)\approx2.6861\\ \\x_2=(5-√(33))/(4)\approx-0.1861`