Question

Determine the equation of a parabola that intersects the x-axis at points (-2, 0) and (5, 0).

A. y= x² – 10

B. y=x² - 3x – 10

C. y=x² + 3x – 10

D. y = x² – 2x + 5​​

Answer 1

The answer is B

Explanation:

1) Since the roots are -2, and 5 we can write this

y=a(x+2)(x-5)

y=a(x²-5x+2x+10)

y=a(x²-3x -10)

2) Examining the options, we can see that all of those options have a=1

Then we can plug into that

y=a(x²-3x -10)

y=x² -3x -10

That's the same as

y=(x+2)(x-5) then its roots are x_1 =-2 , and x_2=5

Answer 2

B. y = x² - 3x - 10

Explanation:

good luck, i hope this helps :)