Question

A mass attached to the end of a spring is oscillating with a period of 2.25 s on a horizontal frictionless surface. The mass was released from rest at

t = 0
from the position
x = 0.0480 m.
Determine the location of the mass at
t = 5.85 s?

Answer 1

`X=0.0389m`

Step-by-step explanation:

From the question we are told that:

Period of spring
`T_s=2.25s`

Initial Position of Mass
`x=0.0480m`

Final Mass period
`T_f=5.85s`

Generally the equation for the Mass location is mathematically given by

`X=xcos*(2\pi T_s)/(T_f)`

`X=0.048*cos*(2\pi 5.85)/(2.25)`

`X=0.0389m`