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In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and HI = 69 feet. Find the length of IJ to the nearest tenth of a foot.

User J Marlow
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2 Answers

9 votes

Answer:

yeeet

Explanation:

User Deepbrook
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6 votes

Answer:

IJ = 68.6 feet

Explanation:

In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and HI = 69 feet. Find the length of IJ to the nearest tenth of a foot.

We solve the above question using the Trigonometric function of Sine

sin x = Opposite/Hypotenuse

x = ∠H=84°

Opposite = IJ

Hypotenuse = HI = 69 feet.

Hence

sin 84 = IJ/69

Cross Multiply

IJ = sin 84 × 69

IJ = 68.62201078 feet

Approximately = 68.6 feet

User Kizzy
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