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2Na + Cl₂ --> 2NaCl, if you start with 0.50 mol of sodium and you ultimately produce 0.43 mol in lab, what is your percent yield?

User Veronika
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1 Answer

12 votes

Answer:

86% is the percent yield of the reaction

Step-by-step explanation:

Percent yield is defined as 100 times the ratio of actual yield / theoretical yield.

Based on the reaction:

2Na + Cl₂ → 2NaCl

The theoretical yield is 0.50 moles because 0.50 mol of Na are added in the beginning. As 0.43 moles are produced, actual yield is 0.43 mol. And percent yield is:

0.43mol / 0.50mol * 100 =

86% is the percent yield of the reaction

User Rahma Samaroon
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