Question

Find the 96th term of the arithmetic sequence -3, -14, -25,

Answer 1

-1048

Explanation:

Use the formula

`a_(n) = a_(1) + (n - 1)d`

d = -14 - (-3) = -25 - (-14) = -11

In your problem, the first term is -3, n = 96, d = -11

`a_(96) = -3 + (96 - 1)(-11)\\ = - 3 + 95(-11)\\ = -3 - 1045\\ = -1048`