Answer:
1) 10cos ( 2πfct + 10sin 2πfmt )
2) 50 watts
3) 1000 Hz
Step-by-step explanation:
m(t) = 10cos(1000πt)
c(t) = 10cos(2πfct )
modulation index ( = 10
1) expression for modulated signal ( u(t) )
u(t) = Ac(cos 2πfct ) + A (cos 2πfct m(t) ) Am cos2πf mt
= 10cos 2πfct + 100 cos 2πfct cos2π500t
= 10cos ( 2πfct + 10sin 2πfmt )
2) power of modulated signal
power of modulated signal μ^2 / 2 ]
= 10^2/2 ]
= 50 watts
3) Bandwidth
B = 2fm = 2 * 500 = 1000 Hz