Question

C + O2 = CO2

If 12g of C reacts with 40g of O2, How much CO2 will be formed? State the law which governs your answer. (5 Mark)

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Answer 1

44 g CO₂

Step-by-step explanation:

The chemical equation for the reaction is:

C(s) + O₂(g) → CO₂(g)

Thus, 1 mol of C(s) reacts with 1 mol of O₂. We convert the moles to grams by using the molecular weight of each compound (C= 12 g/mol; O₂= 32 g/mol):

1 mol C(s) = 12 g/mol x 1 mol = 12 g

1 mol O₂= 32 g/mol x 1 mol = 32 g

The stoichiometric ratio C(s)/O₂ is 12 g C/32 g O₂. We have 40 g of O₂, so it will be consumed:

40 g O₂ x 12 g C/32 g O₂= 15 g C(s)

And we have 12 g. Thus, the limiting reactant is C(s).

Now, we use the limiting reactant to calculate the mass of product produced (CO₂)

Molecular weight CO₂ = 12 g/mol x 1 C + (16 g/mol x 2 O) = 44 g/mol

1 mol CO₂ = 44 g/mol x 1 mol = 44 g

So, 44 grams of CO₂ are produced from 12 g of C(s) (44 g CO₂/12 g C). So, the amount produced when 12 g of C(s) reacts with 40 g O₂ is:

12 g C(s) x 44 g CO₂/12 g C(s) = 44 g