Question

The perimeter of a rectangular

field is 628m.the length of the field exceeds its width by 6m.find the dimensions​

Answer 1

154m , 160m

Explanation:

Let width of the rectangle = w

Length = w + 6

Perimeter of rectangle = 628 m

2( length + width ) = 628

2( w + 6 + w) = 628 {Combine like terms}

2*( 2w +6 ) = 628 {Distributive property}

2*2w + 2*6 = 628

4w + 12 = 628 {subtract 12 from both sides}

4w = 628 - 12

4w = 616 {Divide both sides by 4}

w = 616/4

w = 154 m

Length = w + 6 = 154 + 6 = 160 m