Question

5. Two charged particles are separated by a distance of 12 meters. The Coulomb force between them is 20 N. What will the Coulomb force be if the same particles are

separated by a distance of 6 meters?
O A 80 N
OB. 40 N
O C. 10N
O D5N

Answer 1

The electrostatic force between two charged particles will increase to 80 N when their separation distance is reduced from 12 meters to 6 meters, in accordance with Coulomb's law.

Step-by-step explanation:

The subject of this question is Physics, specifically focusing on Coulomb's law, which describes the electrostatic force between charged particles. According to Coulomb's law, the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. When the distance between the charged particles is reduced by half, the inverse square law indicates that the force will increase by a factor of four (since 122 is four times smaller than 62).

If two charged particles are initially separated by a distance of 12 meters and the electrostatic force between them is 20 N, reducing the distance between them to 6 meters would increase the force to 80 N. This is because the force increases by the square of the distance ratio, which in this case is (12/6)2 = 4. Therefore, the new force is 20 N * 4 = 80 N.

Answer 2

A) 80 N

Step-by-step explanation:

The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.