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Please i need help with #12 and #13!!!

Please i need help with #12 and #13!!!-example-1
User JMRC
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1 Answer

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Answer:

12. median: AD; altitude: CE; midsegment: none

13. x = 2

Explanation:

12. The median joins a vertex with the midpoint of the opposite side. Point D is identified as the midpoint of BC, so AD is the median.

An altitude is a segment from a vertex that is perpendicular to the opposite side. CE is an altitude of this triangle.

A midsegment joins midpoints of adjacent sides of the triangle. Only one midpoint (D) is identified in this triangle, so no midsegment can be named.

Additional comment: BF is an angle bisector. Perhaps that is what is intended in part (c). You may want to report this question to your teacher.

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13. The base segment is twice the length of the midsegment:

2(5x -3) = x +12

10x -6 = x +12 . . . . . eliminate parentheses

9x = 18 . . . . . . . . . . add 6-x

x = 2 . . . . . . . . . . . . .divide by 9

User Sam Kingston
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