Question

Two plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.50 nC . Ball 1 is negatively charged, and ball 2 is positively charged. The balls are held apart by a 900-mm stick stuck through the holes so that it runs from the center of one ball to the center of the other.

Required:
What is the magnitude of the dipole moment of the arrangement?

Answer 1

The dipole moment is 4.5 x 10^-10 Cm.

Step-by-step explanation:

Charge on each ball, q = 0.5 nC

Length, L = 900 mm = 0.9 m

The dipole moment is defined as the product of either charge and the distance between them.

It is a vector quantity and the direction is from negative charge to the positive charge.

The dipole moment is

`p = q L\\\\p = 0.5 * 10^(-9)* 0.9\\\\p = 4.5* 10^(-10) Cm`

Answer 2

The right solution is "
`4.5* 10^(-10) \ Cm`".

Step-by-step explanation:

Given that,

q = 0.50 nC

d = 900 mm

As we know,

⇒
`P=qd`

By putting the values, we get

⇒
`=0.50* 900`

⇒
`=(0.50* 10^(-9))* 0.9`

⇒
`=4.5* 10^(-10) \ Cm`