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The path of a toy rocket fired into the air can be represented by the equation h= -16t^2+75t. What is the height of the rocket after 3 seconds?

User Bento
by
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1 Answer

11 votes

Answer:

81 units

Explanation:

Given data

We are given the function for the height, the height is a function of time t

h=-16t^2+75t

Hence for t= 3 , let us substitute and find the height h

h=-16(3)^2+75(3)

h= -16*9+ 225

h= -144+ 225

h= 81

Hence the height at 3 seconds is 81 units

User Kriss
by
7.6k points
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