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What is the force on a 1000 kg elevator that is falling freely at 9.8 m/ sec²? ​
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What is the force on a 1000 kg elevator that is falling freely at 9.8 m/ sec²? ​

User Taylorcressy
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1 Answer

10 votes

Answer:

f=m.a 1000*9.8=9800newton

User Mbr
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