Question

asked Jul 21, 2022 60.8k views

2 Answers

Bob Marti · Answer 1 · 2022-07-24T01:28:15+0000

Answer:

$\displaystyle 3) \boxed{ \rm {43.5 \: cm}^(2) }$

$\displaystyle 4)\rm \boxed{112 {cm}^(2) }$

Explanation:

we are given a triangle and we want to figure out the area of it Since we are given the base and the height we can consider the following formula

$\displaystyle (1)/(2) bh$

from the triangle we can assume base and height as 14.5 and 8 respectively Thus substitute:

$\displaystyle (1)/(2) (14.5cm)(6cm)$

reduce fraction:

$\displaystyle (14.5cm)(3cm)$

simplify multiplication:

$\displaystyle \boxed{ \rm {43.5 \: cm}^(2) }$

our given shape is trapezoid

therefore recall that,

$\displaystyle A _{ \text{trapezoid}} = (a + b)/(2) h$

from the shape we define that

now substitute:

$\displaystyle \rm A _{ \text{trapezoid}} = (9cm + 19cm)/(2) (8cm)$

reduce fraction:

$\displaystyle \rm A _{ \text{trapezoid}} = (9cm + 19cm)(4cm)$

simplify addition:

$\displaystyle \rm A _{ \text{trapezoid}} = (28cm)(4cm)$

simplify multiplication:

$\displaystyle \rm A _{ \text{trapezoid}} = \boxed{112 {cm}^(2) }$

Mithilatw · Answer 2 · 2022-07-26T05:01:06+0000

Answer:

43.5 cm² and 112 cm²

Explanation:

Here the instructions aren't given what to do. So I am finding the area of the ∆s .

Area of first ∆ :-

Area of second ∆ :-

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