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Helpppppppppp anyone know algebra?

Helpppppppppp anyone know algebra?-example-1

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Answer:

5x/7y^3

Explanation:

Something to the power of -1/2 is saying 1 over square-root of that something. Let's pretend x is that something. If we have something like this
x^{-(1)/(2) }, then it can be written like this:
(1)/(√(x)).

In our problem, we have the chunk to the -1/2 power. So the reciprocal of the chunk would become
\sqrt{(25x^(2) )/(49y^(6))

It's easy to solve now. The square root of the numerator becomes 5x and the denominator becomes 7y^3. The simplified version is
\frac{5x}{7y^\power{3}}

User Craig Warren
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