Question

Let a and b be the solutions to x^2 + x − 3 = 0. Find the value of a^3 − 4b^2 + 19.

If you can't solve it don't answer.
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Answer 1

0.037

Explanation:

Given that,

Let a and b be the solutions to
`x^2 + x -3 = 0`

It can be solved using quadratic formula where a = 1, b = 1 and c = -3

So,

`x=(-1+√(1^2-4* 1* (-3)))/(2(1)),(-1-√(1^2-4* 1* (-3)))/(2(1))\\\\x=1.30,-2.3`

Let a = 1.3, b = -2.3

The value of
`a^3 -4b^2 + 19` can be given by :

`a^3 -4b^2 + 19=(1.3)^3-4* (-2.3)^2+19\\\\=0.037`

So, the value of the given expression is 0.037.