Question

Suppose a scoentist was able to construct a barometer with a liquid being denser than mercury , then how high would the liquid raise at standard pressure

Answer 1

the liquid has less height than the mercury

h_{ liquid} =
`(\rho_(Hg) )/(\rho_(liqid)) \ h_(Hg)`

Step-by-step explanation:

The pressure as a function of the height is given by

P = ρ g h

where ρ is the density of the liquid, g the acceleration of gravity and h the height reached by the column of the liquid

In that case they say that the pressure is the standard one that is P = 1.01 10⁵ Pa = 760 mmHg

The first way to give the pressure is in SI units and the second way is the height that the mercury column reaches

In the case of building a barometer with a liquid that has a density greater than that of mercury

ρ_liquid > ρ_Hg

the pressure

P =ρ_lquid g h_liquid

if we have the same pressure

ρ_{Hg} g h_{Hg} = ρ_{liquid} g h_{liquid}

h_{ liquid} =
`(\rho_(Hg) )/(\rho_(liqid)) \ h_(Hg)`

therefore the liquid has less height than the mercury