Part 1
If we simplify, both Joe and Hope factored the polynomial correctly but Joe didn't complete it fully.
The first binomial can be further factored:
Part 2
The quadratic expression needs to have two roots in order to be factored as two binomials.
The discriminant must be positive or zero:
We have a = 3, b = k, c = -8
So we get following inequality:
- k² - 4*3*(-8) ≥ 0
- k² + 96 ≥ 0
Since k² is positive for any value of k, the solution is any value of k: