Given:
The slope of the line is m=0.
The line passes through the point P(-9,-3).
To find:
The equation of the line in standard form.
Solution:
Standard form of a line is:
![Ax+By=C](https://img.qammunity.org/2022/formulas/mathematics/college/8xoz07pf621d3x897kf2gf8rrbctwqk4qo.png)
The slope intercept form of the line is
![y-y_1=m(x-x_1)](https://img.qammunity.org/2022/formulas/mathematics/middle-school/vtillwnvtmv4154m1gj6eh3pnty0mf96g6.png)
Where, m is the slope and
is the point on the line.
It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is
![y-(-3)=0(x-(-9))](https://img.qammunity.org/2022/formulas/mathematics/college/dexe9r4y47gcj496resokpzwu62odjerfq.png)
![y+3=0](https://img.qammunity.org/2022/formulas/mathematics/college/wpwohy0s0tix4dvuja7l85n2jr3tsv78si.png)
![y=-3](https://img.qammunity.org/2022/formulas/mathematics/college/zucde9rbx5t81v33o38yunxgjtqnfbia3r.png)
Therefore, the standard form of the given line is
.