Question

Write the balanced half-equations for silver + oxygen= silver oxide:

Answer 1

Answer: The balanced half-equations for silver + oxygen= silver oxide are:

Oxidation-half reaction:
`Ag \rightarrow 2Ag^(+) + 2e^(-)`

Reduction-half reaction:
`O_(2) + 2e^(-) \rightarrow 2O^(-)`

Step-by-step explanation:

The word equation is as follows.

silver + oxygen = silver oxide

In terms of chemical formulas this equation can be written as follows.

`Ag + O_(2) \rightarrow Ag_(2)O`

The removal on electron(s) from an atom, ion or molecule in a chemical reaction is called oxidation.

The gain of electron(s) by an atom, ion or molecule in a chemical reaction is called reduction.

Hence, half-reaction equations for the given reaction is as follows.

Oxidation-half reaction:
`Ag \rightarrow 2Ag^(+) + 2e^(-)`

Reduction-half reaction:
`O_(2) + 2e^(-) \rightarrow 2O^(-)`

As the number of atoms participating in the reaction are equal. Hence, the half-equations are balanced.

Thus, we can conclude that the balanced half-equations for silver + oxygen = silver oxide are:

Oxidation-half reaction:
`Ag \rightarrow 2Ag^(+) + 2e^(-)`

Reduction-half reaction:
`O_(2) + 2e^(-) \rightarrow 2O^(-)`