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29 votes
29 votes
In order to keep a leaking ship from sinking, it is necessary to pump 12.0 lb of water each second from below deck up a height of 2.00 m and over the side. What is the minimum horse-

power motor that can be used to save the ship?

User Clay Risser
by
3.2k points

1 Answer

16 votes
16 votes

Answer:

P = 0.14 hp

Step-by-step explanation:

The power required by the ship is given as:


P = (Work)/(Time) = (Potential\ Eenrgy)/(t)\\\\P = (mgh)/(t)

where,

P = Power = ?

m = mass to pump = (12 lb)(1 kg/2.20 lb) = 5.44 kg

g = acceleration due to gravity = 9.81 m/s²

h = height = 2 m

t = time = 1 s

Therefore,


P = ((5.44\ kg)(9.81\ m/s^2)(2\ m))/(1\ s)\\\\P = 106.8\ W

Converting to horsepower (hp):


P = (106.8\ W)((1\ hp)/(746\ W))

P = 0.14 hp

User Oli Crt
by
2.9k points