Question

What is the rate constant of a reaction if rate = 1 x 10^-2 (mol/L)/s, [A] is 2 M,

[B] is 3 M, m = 2, and n= 1?

k= rate
[A] [BT]

A. 1.7 x 10-3
B. 2.5 x 10-3
C. 6.0 x 10-3
D. 8.3 x 10-4

Answer 1

D. 8.3 x 10-4

Step-by-step explanation:

Hello!

In this case, since the rate law is written solving for the rate constant as:

`k=(r)/([A]^2[B])`

Thus, we plug the rate and concentrations to obtain:

`k=(0.01M/s)/((2M)^2(3M))\\\\k=8.3x10^(-4)M^(-2)s^(-1)`

Therefore, the answer would be D. 8.3 x 10-4

Best regards!