Question

A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Newtons. What is the frequency of this mode of vibration

Answer 1

the frequency of this mode of vibration is 138.87 Hz

Step-by-step explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

`F_n = (n)/(2L) \sqrt{(T)/(\mu) } \\\\F_2 = (2)/(2* 1) \sqrt{(27)/(0.0014) }\\\\F_2 = 138.87 \ Hz`

Therefore, the frequency of this mode of vibration is 138.87 Hz