Question

The slope of diagonal OA is ? and its equation is ?

Answer 1

Slope =
`(4)/(3)`

Equation of the line →
`y=(4)/(3)x`

Explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points
`(x_1,y_1)` and
`(x_2,y_2)` is given by,

m =
`(y_2-y_1)/(x_2-x_1)`

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m =
`(4-0)/(3-0)`

m =
`(4)/(3)`

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

`y=(4)/(3)x`