Question

Jacky leaves the office at 4:15 PM. If

she reaches her house at 4:55 PM
when her house is 25 km away from
her office, approximately, how fast did
she drive?

Answer 1

Given:

Jacky leaves the office at 4:15 PM and she reaches her house at 4:55 PM.

Distance between office and her house = 25 km

To find:

The driving speed of Jacky.

Solution:

The difference between 4:15 PM and 4:55 PM is 40 minutes.

60 minute = 1 hour

1 minute =
`(1)/(60)` hour

40 minute =
`(40)/(60)` hour

=
`(2)/(3)` hour

We know that,

`Speed=(Distance)/(Time)`

`Speed=(25)/((2)/(3))`

`Speed=(3* 25)/(2)`

`Speed=(75)/(2)`

`Speed=37.5`

Therefore, the driving speed of Jacky is 37.5 km per hour.