Question

Suppose y varies inversely with X, and y = 36 when x = 1/12. What inverse variation equation relates x and y?

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a. y= 3x
b. y= 3/x
c. x/3
d. y= x​

Answer 1

B

Explanation:

We are given that y varies inversely with x. Recall that inverse variation has the form:

`\displaystyle y=(k)/(x)`

Where k is the constant of variation.

We are given that y = 36 when x = 1/12. Thus:

`\displaystyle (36)=\frac{k}{\left({}^(1)\!/\!{}_(12)\right)}`

Solve for k. Multiply both sides by 1/12:

`\displaystyle k=(1)/(12)(36)=3`

Hence, our equation is:

`\displaystyle y=(3)/(x)`

Our answer is B.