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6 votes
6 votes
Suppose y varies inversely with x, and y = 18 when x = 12. What is the value of x when y = 24? NO LINKS OR ANSWERING YOU DON'T KNOW?

a. 24
b. 9
c. 12
d. 18​

User Zanson
by
3.2k points

2 Answers

26 votes
26 votes

Answer:

B. 9

Explanation:

We are given that y varies inversely with x. Recall that inverse variation has the form:


\displaystyle y=(k)/(x)

Where k is the constant of variation.

We are given that y = 18 when x = 12. Hence:


\displaystyle (18)=(k)/((12))

Solve for k. Multiply both sides by 12:


k=12(18)=216

Thus, our equation is:


\displaystyle y=(216)/(x)

We want to find x when y = 24. Substitute:


\displaystyle (24)/(1)=(216)/(x)

Cross-multiply:


24x=216

Divide both sides by 24. Hence:


x=9

Our answer is B.

User Annath
by
2.6k points
15 votes
15 votes

Answer:

B

Explanation:

Given that y varies inversely with x then the equation relating them is

y =
(k)/(x) ← k is the constant of variation

To find k use the condition y = 18 when x = 12 , then

18 =
(k)/(12) ( multiply both sides by 12 )

216 = k

y =
(216)/(x) ← equation of variation

When y = 24 , then

24 =
(216)/(x) ( multiply both sides by x )

24x = 216 ( divide both sides by 24 )

x = 9

User Ahmad Kayyali
by
3.6k points
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