Suppose that two balanced, six sided dice are tossed repeatedly and the sum of the two uppermost faces is determined on each toss. (a) What is the probability that we obtain a sum of 3 before we obtain

Laquinta asked Jul 24, 2022

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Laquinta asked Jul 24, 2022

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22 votes

Answer:

((2/36))/((1-(28/36))) = 1/4

Explanation:

Gabbler answered Jul 31, 2022

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