433,964 views
20 votes
20 votes
100 g of water are cooled and the enthalpy change is -12,540 J. What is the change in temperature of the water?

User Jmegaffin
by
2.9k points

1 Answer

16 votes
16 votes

Answer:

-29.9907

Step-by-step explanation:

c = Q / (mΔT)

You're looking for ΔT, so you would plug in what you already know and get C= -12540/(100 x ΔT)

then you would solve

User Priyanka Mishra
by
3.5k points