Final Answer:
The zeros of the quadratic equation y = x^2 - x - 5 are x = -1 ± √19.
Step-by-step explanation:
We can find the zeros of the quadratic equation using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = -1, and c = -5. Substituting these values:
x = (-(-1) ± √((-1)^2 - 4 * 1 * -5)) / 2 * 1
x = (1 ± √(1 + 20)) / 2
x = (1 ± √21) / 2
Therefore, the zeros of the equation are:
x = (1 + √21) / 2 ≈ 3.618
x = (1 - √21) / 2 ≈ -2.618
Combining these solutions, the zeros of the quadratic equation y = x^2 - x - 5 are x = -1 ± √19.