Now we have to,
find the three angles if one angle is twice smallest angle and third angle is 36° greater than smallest angle.
Then take the values as,
→ smallest angle = x
→ y = 2x
→ z = x + 36°
Let we find the angles,
→ x + y + z = 180°
→ x + 2x + x + 36° = 180°
→ 4x = 180 - 36
→ 4x = 144
→ x = 144/4
→ [x = 36°]
Now the value of y is,
→ y = 2x
→ y = 2 × 36°
→ [y = 72°]
Then the value of z is,
→ z = x + 36°
→ z = 36° + 36°
→ [z = 72°]
Placing values from least to greatest,
→ 36°, 72°, 72°
Hence, the order is 36°, 72°, 72°.