Explanation:
Given
f(x) = 5 / 2x - 1
f^-1( x) = ?
Let
y = f(x)
y = 5/2x - 1
Interchanging the roles of x and y we get
x = 5/2y - 1
2y - 1 = 5/x
2y = 5/x - 1
y = (5/x - 1)/ 2
f^-1(x) = ( 5/x - 1) / 2
Hope it will help :)
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