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In ΔOPQ, q = 83 inches, p = 80 inches and ∠P=70°. Find all possible values of ∠Q, to the nearest degree

1 Answer

5 votes

Answer:

77.12°

Explanation:

Given that:

In triangle OPQ

∠P=70°

line q = 83 inches

line p = 80 inches

To find ∠Q; we use the since rule:


(Sin \ Q)/(q) = (Sin \ P)/(p)


(Sin \ Q)/(83) = (Sin \ 70)/(80)


Sin \ Q= (Sin \ 70 * 83)/(80)


\text{Sin \ Q= 0.9749}


Q=Sin ^(-1)( 0.9749)


\mathbf{Q = 77.12^0}

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