Question

An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied downward. What is the net force on the object?

Answer 1

the net force on the object is 6 N.

Step-by-step explanation:

Given;

force applied to the right on the object,
`F_r` = 16 N

force applied to the left of the object,
`F_l` = 16 N

force applied downward on the object,
`F_d` = 6 N

The net horizontal force on the object =
`F_r - F_l = 16N -16N = 0`

The net vertical force on the object =
`6 \ N \ downward`

The net force on the object is calculated as;

`F_(net)^2 = 6^2 + 0\\\\F_(net)^2 = 36\\\\F_(net) = √(36) \\\\F_(net) = 6 \ N`

Therefore, the net force on the object is 6 N.