Question

CaF2 + (NH4)2O --> 2 NH4F + CaO How many grams of NH4F can be formed from 34.6 grams of CaF2? (AKS 4f)

Answer 1

32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂

Step-by-step explanation:

The balanced reaction is:

CaF₂ + (NH₄)₂O ⇒ 2 NH₄F + CaO

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following quantities participate in the reaction:

• CaF₂: 1 mole
• (NH₄)₂O: 1 mole
• NH₄F: 2 mole
• CaO: 1 mole

Being the molar mass of the compounds:

• CaF₂: 78 g/mole
• (NH₄)₂O: 52 g/mole
• NH₄F: 37 g/mole
• CaO: 56 g/mole

Then by stoichiometry, the following amounts of mass participate in the reaction:

• CaF₂: 1 mole* 78 g/mole= 78 g
• (NH₄)₂O: 1 mole* 52 g/mole= 52 g
• NH₄F: 2 mole* 37 g/mole= 74 g
• CaO: 1 mole* 56 g/mole= 56 g

You can apply the following rule of three: if 78 grams of CaF₂ form 74 grams of NH₄F by stoichiometry, 34.6 grams of CaF₂ will form how much mass of NH₄F?

`mass of NH_(4) F=(34.6 grams of CaF_(2) *74 grams ofNH_(4) F)/(78grams of CaF_(2) )`

mass of NH₄F= 32.83 grams

32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂