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Find, to the nearest foot, the length of the diagonal of a square whose side is 8 feet.
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Find, to the nearest foot, the length of the diagonal of a square whose side is 8 feet.

User Harrane
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1 Answer

8 votes
8 votes
a^2 + b^2 = c^2
8^2 + 8^2 = c^2
64 + 64 = c^2
128 = c^2
squareroot 128 = c
11.3.... = c
so to the nearest foot the length of the diagonal is 11 feet
User Moddaman
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