Question

Find the transformation matrix that rotates a rectangular coordinate system through an angle of 60 about axes equal angels with original three coordinate axes

Answer 1

`M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]`

Step-by-step explanation:

To find the matrix, let's decompose the vectors, the rotated angle is (-60C) for the prime system

x ’= x cos (-60)

y ’= y sin (-60)

we use

cos 60 = cos (-60)

sin 60 = - sin (-60)

we substitute

x ’= x cos 60

y ’= - y sin 60

the transformation system is

`\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}cos 60&0\\0&-sin60\end{array}\right] \ \left[\begin{array}{ccc}x\\y\end{array}\right]`x '

the transformation matrix is

`M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]`