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If you were to hit a Ping Pong ball of mass 0.0029 gg with the same force that caused a 0.058-gg tennis ball to move with an acceleration of 10 m/s2m/s2 , what would the acceleration aaa of the Ping Pong ball be

User Egretos
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6 votes

Answer:

the acceleration of the Ping Pong ball is 200 m/s²

Step-by-step explanation:

Given;

mass of Ping Pong ball, m = 0.0029 g = 2.9 x 10⁻⁶ kg

mass of tennis ball, m = 0.058 g = 5.8 x 10⁻⁵ kg

acceleration of the tennis ball, a = 10 m/s²

The force applied to the tennis ball is calculated as;

F = ma

F = 5.8 x 10⁻⁵ x 10

F = 5.8 x 10⁻⁴ N

The acceleration of the Ping Pong ball is calculated as;

a = F/m

a = ( 5.8 x 10⁻⁴ N) / (2.9 x 10⁻⁶)

a = 200 m/s²

Therefore, the acceleration of the Ping Pong ball is 200 m/s²

User Tom Aarsen
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